Answer:
It remains zero
Explanation:
The work done on an object is given by:
[tex]W=Fd cos \theta[/tex]
where
F is the magnitude of the force applied
d is the displacement of the object
[tex]\theta[/tex] is the angle between the direction of the force and of the displacement
In this problem, the object is the wall, which is stationary. Therefore, the displacement of the wall is zero:
d = 0
And so, the work done is always zero, even if the force applied is twice as stronger.
