Answer:
230 kJ
Explanation:
The amount of heat needed to melt a substance at its melting point is:
[tex]Q=m\lambda_f[/tex]
where
m is the mass of the substance
[tex]\lambda_f[/tex] is the latent heat of fusion of the substance
In this problem,
m = 10.0 kg is the mass of the lead sample
[tex]\lambda_f = 23 kJ/kg[/tex] is the latent heat of fusion of lead
Substituting,
[tex]Q=(10.0 kg)(23 kJ/kg)=230 kJ[/tex]
Answer:
Q = 230 kJ
Explanation:
Heat required to melt a given matter at its melting point is given by latent heat of fusion
It will remain constant for a given metal
for lead the latent heat of fusion is given as
[tex]L = 23 kJ/kg[/tex]
now we know that
[tex]Q = mL[/tex]
here m = 10 kg
so heat required to melt 10 kg of lead is given as
[tex]Q = 10 \times 23[/tex]
[tex]Q = 230 kJ[/tex]
