Answer:
Electric field, E = 2 N/C
Explanation:
It is given that,
Mass of an electron, [tex]m=9.1\times 10^{-31}\ kg[/tex]
Electric force, [tex]F=3.2\times 10^{-19}\ N[/tex] (in +x direction)
We have to find the electric field at this point. The electric field is given by the electric force acting on a charged particle per unit electric charge. Mathematically, it is given by :
[tex]E=\dfrac{F}{q}[/tex]
q = charge on an electron, [tex]1.6\times 10^{-19}\ C[/tex]
[tex]E=\dfrac{3.2\times 10^{-19}\ N}{1.6\times 10^{-19}\ C}[/tex]
E = 2 N/C
The electric field at this point is 2 N/C.
