Answer: 1527
Step-by-step explanation:
Given: Mean : [tex]\mu = 3234\text{ grams}[/tex]
Standard deviation : [tex]\sigma=871\text{ grams}/tex]
Sample size : [tex]n=1600[/tex]
The formula to calculate the z score is given by :-
[tex]z=\dfrac{X-\mu}{\sigma}[/tex]
For X=1492
[tex]z=\dfrac{1492-3234}{871}=-2[/tex]
The p-value of z =[tex]P(z<-2)=0.0227501[/tex]
For X=4976
[tex]z=\dfrac{4976-3234}{871}=2[/tex]
The p-value of z =[tex]P(z<2)=0.9772498[/tex]
Now, the probability of the newborns weighed between 1492 grams and 4976 grams is given by :-
[tex]P(1492<X<4976)=P(X<4976)-P(X<1492)\\\\=P(z<2)-P(z<-2)\\\\=0.9772498-0.0227501\\\\=0.9544997[/tex]
Now, the number newborns who weighed between 1492 grams and 4976 grams will be :-
[tex]1600\times0.9544997=1527.19952\approx1527[/tex]