Answer:
The radius of the disc is 2.098 m.
(e) is correct option.
Explanation:
Given that,
Moment of inertia I = 12100 kg-m²
Mass of disc m = 5500 kg
Moment of inertia :
The moment of inertia is equal to the product of the mass and square of the radius.
The moment of inertia of the disc is given by
[tex]I=\dfrac{mr^2}{2}[/tex]
Where, m = mass of disc
r = radius of the disc
Put the value into the formula
[tex]12100=\dfrac{5500\times r^2}{2}[/tex]
[tex]r=\sqrt{\dfrac{12100\times2}{5500}}[/tex]
[tex]r= 2.098\ m[/tex]
Hence, The radius of the disc is 2.098 m.
