Answer:
The car's centripetal acceleration is 1.22 m/s².
Explanation:
Given that,
Diameter of circular track [tex]d= 1.00\ km=1000\ m[/tex]
Radius r = 500 m
Constant speed [tex]v = 89\ km/h = 89\times\dfrac{5}{18}=24.722\ m/s[/tex]
The centripetal acceleration is defined as,
[tex]a_{c} = \dfrac{v^2}{r}[/tex]
Where, v = tangential velocity
r = radius
Put the value into the formula
[tex]a_{c}=\dfrac{(24.722)^2}{500}[/tex]
[tex]a_{c}=1.22\ m/s^2[/tex]
Hence, The car's centripetal acceleration is 1.22 m/s².
