contestada

A golfer on a level fairway hits a ball at an angle of 21° to the horizontal that travels 99 yd before striking the ground. He then hits another ball from the same spot with the same speed, but at a different angle. This ball also travels 99 yd. At what angle was the second ball hit? (Neglect air resistance.)

Respuesta :

MathPhys

Answer:

69°

Explanation:

Projectiles that land at the same elevation they're launched from will have the same range if the launch angles are complementary (add up to 90°).

The complement of 21° is 69°.

The second ball hit at a 69° angle.

Why did the second ball hit at a different angle?

  • Projectiles that land at the same elevation they're launched from will have the same range if the launch angles are complementary (add up to 90°).
  • The complement of 21° is 69°.
  • Because at the time of landing, the magnitude of horizontal and vertical components of the velocity is the same as that at the time of release (although the direction of the vertical component is now downwards, as opposed to being upwards during the release).
  • Now, the angle of the projectile at any point of time during the flight is defined by Theta = tan inverse (Vertical component of velocity/Horizontal component of velocity).
  • Hence, the second ball hit at a 69° angle.

To know more information about complementary angles, refer to: https://brainly.com/question/16520123

#SPJ2

Otras preguntas