Answer:
(a) 2.34 s
(b) 6.71 m
(c) 38.35 m
(d) 20 m/s
Explanation:
u = 20 m/s, theta = 35 degree
(a) The formula for the time of flight is given by
[tex]T = \frac{2 u Sin\theta }{g}[/tex]
[tex]T = \frac{2 \times 20 \times Sin35 }{9.8}[/tex]
T = 2.34 second
(b) The formula for the maximum height is given by
[tex]H = \frac{u^{2} \times Sin^{2}\theta }{2g}[/tex]
[tex]H = \frac{20^{2} \times Sin^{2}35 }{2 \times 9.8}[/tex]
H = 6.71 m
(c) The formula for the range is given by
[tex]R = \frac{u^{2} \times Sin 2\theta }{g}[/tex]
[tex]R = \frac{20^{2} \times Sin 2 \times 35}{9.8}[/tex]
R = 38.35 m
(d) It hits with the same speed at the initial speed.
