Answer:
The acceleration is [tex]11.1g\ m/s^2[/tex]
Explanation:
Given that,
Speed [tex]v= 6.50\ km/s=6.5\times10^{-3}\ m/s[/tex]
Time t = 60.0 sec
We need to calculate the acceleration
Using formula off acceleration
[tex]a = \dfrac{\Delta v}{t}[/tex]
[tex]a=\dfrac{v_{f}-v_{i}}{t}[/tex]
We know that,
Missile goes from rest
So, Initial velocity =0
Put the value into the formula
[tex]a =\dfrac{6.50\times10^{3}}{60.0}[/tex]
[tex]a=108.33\ m/s^2[/tex]
On right hand side multiplying and dividing by g = 9.8m/s²
[tex]a=108.33\times\dfrac{g}{g}[/tex]
Put the value of g
[tex]a = \dfrac{108.33}{9.8}g\ m/s^2[/tex]
[tex]a = 11.1g\ m/s^2[/tex]
Hence, The acceleration is [tex]11.1g\ m/s^2[/tex]
