Answer:
Speed of both blocks after collision is 2 m/s
Explanation:
It is given that,
Mass of both blocks, m₁ = m₂ = 1 kg
Velocity of first block, u₁ = 3 m/s
Velocity of other block, u₂ = 1 m/s
Since, both blocks stick after collision. So, it is a case of inelastic collision. The momentum remains conserved while the kinetic energy energy gets reduced after the collision. Let v is the common velocity of both blocks. Using the conservation of momentum as :
[tex]m_1u_1+m_2u_2=(m_1+m_2)v[/tex]
[tex]v=\dfrac{m_1u_1+m_2u_2}{(m_1+m_2)}[/tex]
[tex]v=\dfrac{1\ kg\times 3\ m/s+1\ kg\times 1\ m/s}{2\ kg}[/tex]
v = 2 m/s
Hence, their speed after collision is 2 m/s.
