Explanation:
It is given that,
Initial velocity of the bird, u = 13 m/s
Final speed of the bird, v = 10.5 m/s
Time taken, t = 4.20 s
(a) Acceleration of the bird is given by :
[tex]a=\dfrac{v-u}{t}[/tex]
[tex]a=\dfrac{10.5\ m/s-13\ m/s}{4.20\ s}[/tex]
[tex]a=-0.59\ m/s^2[/tex]
So, The direction of acceleration is opposite to the direction of motion.
(b) We need to find the bird’s velocity after an additional 1.50 s has elapsed i.e. t = 4.2 + 1.5 = 5.7 s. Let v' is the new final velocity.
It can be calculated using first equation of motion as :
[tex]a=\dfrac{v'-u}{t}[/tex]
v' = u + at
[tex]v'=(-0.59)\times 5.7+13[/tex]
v' = 9.64 m/s
Hence, this is the required solution.