Respuesta :
Answer:
[tex]F = (3.9\times 10^3)\hat j - 2.8 \times 10^3\hat i[/tex]
Explanation:
Initial momentum of the ball is given as
[tex]P_i = mv_i[/tex]
[tex]P_i = 0.145 (40) = 5.8 kg m/s \hat i[/tex]
now final momentum of the ball is given as
[tex]P_f = 0.145(57) = 8.3 kg m/s \hat j[/tex]
now by the formula of force we have
[tex]F = \frac{P_f - P_i}{\Delta t}[/tex]
now we have
[tex]F = \frac{8.3 \hat j - 5.8 \hat i}{2.10 \times 10^{-3}}[/tex]
[tex]F = (3.9\times 10^3)\hat j - 2.8 \times 10^3\hat i[/tex]
The average vector force the ball exerts on the bat during their interaction is
[tex]\rm F = 3.9\times10^3\;\hat{j}-2.8\times10^3\;\hat{i}[/tex]
Given :
Initial Speed = 40 m/sec
Final Speed = 57 m/sec
Mass = 0.145 Kg
Time = 0.0021 sec
Solution :
Initial Momentum is,
[tex]\rm P_i = mv_i[/tex]
[tex]\rm P_i = 0.145\times 40 = 5.8\;Kg .m/sec\;\hat{i}[/tex]
Final momentum is,
[tex]\rm P_f = mv_f = 0.145\times57=8.3\; Kg.m/sec\; \hat{j}[/tex]
Now,
[tex]\rm F=\dfrac{P_f-P_i}{\Delta t}= \dfrac{8.3\hat{j}-5.8\hat{i}}{2.10\times10^-^3}[/tex]
[tex]\rm F = 3.9\times10^3\;\hat{j}-2.8\times10^3\;\hat{i}[/tex]
For more information, refer the link given below
https://brainly.com/question/13492374?referrer=searchResults
