Answer: Hence, the probability that the whole shipment would be accepted is 0.371.
Many would be rejected.
Step-by-step explanation:
Since we have given that
Number of tablets to be tested = 42
Probability of getting a defect = 5% = 0.05
We need to find the probability that this whole shipment will be accepted.
As we have mentioned that if there is only one or none defect, then the whole shipment would be accepted.
P(accepted) = P(either none or one defect) = P(X=0)+P(X=1)
[tex]P(X=0)=(1-0.05)^{42}=(0.95)^{42}=0.115\\\\and\\\\P(X=1)=42\times (0.05)(0.95)^{41}=0.006\times 42=0.256[/tex]
So, P(Accepted) = 0.115+0.256=0.371
Hence, the probability that the whole shipment would be accepted is 0.371.
Many would be rejected.