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A 66.2 kg ice skater moving to the right with a velocity of 2.47 m/s throws a 0.136 kg snowball to the right with a velocity of 31.4 m/s relative to the ground. What is the velocity of the ice skater after throwing the snowball? Disregard the friction between the skates and the ice.

Respuesta :

Answer:

v = 2.41 m/s

Explanation:

Here net force on the Skater + snowball is zero

so here we can use momentum conservation for skater + snowball

[tex]m_1v_{1i} + m_2v_{2i} = m_1v_{1f} + m_2v_{2f}[/tex]

now we have

[tex]66.2(2.47) + (0.136)(2.47) = 66.2 (v) + 0.136(31.4)[/tex]

[tex]163.85 = 66.2 v + 4.27[/tex]

[tex]163.85 - 4.27 = 66.2 v[/tex]

[tex]v = \frac{159.6}{66.2}[/tex]

[tex]v = 2.41 m/s[/tex]

so the final speed of skater will be 2.41 m/s

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