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PVC pipe is manufactured with mean diameter of 1.01 inch and a standard deviation of 0.003 inch. Find the probability that a random sample of n = 9 sections of pipe will have a sample mean diameter greater than 1.009 inch and less than 1.012 inch.

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JeanaShupp

Answer: 0.8186

Step-by-step explanation:

Given: Mean : [tex]\mu=1.01\text{ inch}[/tex]

Standard deviation :  [tex]\sigma=0.003\text{ inch}[/tex]

Sample size :  [tex]n=9[/tex]

The formula to calculate z-score :-

[tex]z=\dfrac{X-\mu}{\dfrac{\sigma}{\sqrt{n}}}[/tex]

For x=1.009 inch

[tex]z=\dfrac{1.009-1.01}{\dfrac{0.003}{\sqrt{9}}}=-1[/tex]

For x=1.012 inch

[tex]z=\dfrac{1.012-1.01}{\dfrac{0.003}{\sqrt{9}}}=2[/tex]

Now, The p-value =[tex]P(-1<z<2)=P(2)-P(-1)=0.9772498-0.1586553=0.8185945\approx0.8186[/tex]

Hence, the required probability = 0.8186

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