Answer:
60.00% is the volume percent the ethylene glycol in the antifreeze mixture.
Explanation:
Volume of the ethylene glycol in the mixture = 3.00 gal
Volume of the water in the mixture = 2.00 gal
Total volume of the mixture =3.00 gal + 2.00 gal = 5.00 gal
Volume percent the ethylene glycol :
[tex]\frac{\text{Volume of solute}}{\text{Volume of solution or mixture}}\times 100[/tex]
[tex]\%=\frac{3.00 gal}{5.00 gal}\times 100=60.00\%[/tex]
60.00% is the volume percent the ethylene glycol in the antifreeze mixture.
