Respuesta :
Answer : The mass of copper deposit is, 1.98 grams
Explanation :
First we have to calculate the charge.
Formula used : [tex]Q=I\times t[/tex]
where,
Q = charge = ?
I = current = 10 A
t = time = 10 min = 600 sec (1 min = 60 sec)
Now put all the given values in this formula, we get
[tex]Q=10A\times 600s=6000C[/tex]
Now we have to calculate the number of atoms deposited.
As, 1 atom require charge to deposited = [tex]2\times (1.6\times 10^{-19})[/tex]
Number of atoms deposited = [tex]\frac{(6000)}{2\times(1.6\times 10^{-19})}=1.875\times 10^{22}[/tex] atoms
Now we have to calculate the number of moles deposited.
Number of moles deposited = [tex]\frac{(1.875\times 10^{22})}{(6.022\times 10^{23})}=0.03113[/tex] moles
Now we have to calculate the mass of copper deposited.
1 mole of Copper has mass = 63.5 g
Mass of Copper Deposited = [tex]63.5\times 0.03113 =1.98g[/tex]
Therefore, the mass of copper deposit is, 1.98 grams
