Respuesta :
Answer: The volume of CO formed is 254.43 L.
Explanation:
To calculate the number of moles, we use the equation:
[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}[/tex]
Given mass of [tex]Ni(CO)_4[/tex] = 444 g
Molar mass of [tex]Ni(CO)_4[/tex] = 170.73 g/mol
Putting values in above equation, we get:
[tex]\text{Moles of }Ni(CO)_4=\frac{444g}{170.73g/mol}=2.60mol[/tex]
For the given chemical reaction:
[tex]Ni(CO)_4(l)\rightarrow Ni(s)+4CO(g)[/tex]
By stoichiometry of the reaction:
1 mole of nickel tetracarbonyl produces 4 moles of carbon monoxide.
So, 2.60 moles of nickel tetracarbonyl will produce = [tex]\frac{4}{1}\times 2.60=10.4mol[/tex] of carbon monoxide.
Now, to calculate the volume of the gas, we use ideal gas equation, which is:
PV = nRT
where,
P = Pressure of the gas = 752 torr
V = Volume of the gas = ? L
n = Number of moles of gas = 10.4 mol
R = Gas constant = [tex]62.364\text{ L Torr }mol^{-1}K^{-1}[/tex]
T = Temperature of the gas = [tex]22^oC=(273+22)K=295K[/tex]
Putting values in above equation, we get:
[tex]752torr\times V=10.4mol\times 62.364\text{ L Torr }mol^{-1}K^{-1}\times 295K\\\\V=254.43L[/tex]
Hence, the volume of CO formed is 254.43 L.
