Answer with Explanations:
Given:
Mass of object, m = 100 lb
height fallen, h = 600 ft
initial velocity, u = 50 ft/s
acceleration due to gravity, g = 31.5 ft/s^2
Find final velocity when it touches ground.
Solution:
Use standard kinematics equation, in the absence of air resistance and variation of g with height,
v^2 - u^2 = 2aS
where
v = final velocity
u = initial velocity
a = acceleration due to gravity
S = distance travelled
Substitute values
v^2 = u^2 + 2aS
= 50^2 + 2*31.5*600
= 40300 ft^2/s^2
Final velocity,
v = sqrt(40300) ft/s
= 200.75 ft/s
= 201 ft/s to the nearest foot.
