Answer:
The angle the wire make with respect to the magnetic field is 30°
Explanation:
It is given that,
Length of straight wire, L = 0.6 m
Current carrying by the wire, I = 2 A
Magnetic field, B = 0.3 T
Force experienced by the wire, F = 0.18 N
Let θ be the angle the wire make with respect to the magnetic field. Magnetic force is given by :
[tex]F=ILB\ sin\theta[/tex]
[tex]\theta=sin^{-1}(\dfrac{F}{ILB})[/tex]
[tex]\theta=sin^{-1}(\dfrac{0.18\ N}{2\ A\times 0.6\times 0.3\ T})[/tex]
[tex]\theta=30^{\circ}[/tex]
So, the angle the wire make with respect to the magnetic field is 30°. Hence, this is the required solution.
