Answer:
K in KClO2 = +1
Cl in KClO2 = +3
O in KClO2 = -2
K in KCl = +1
Cl in KCl = -1
O in O2 = 0
Chlorine is going from +3 to -1 so it is being reduced
Oxygen is going from -2 to 0 so it is being oxidized
Explanation:
Potassium is a constant +1
Chlorine could be -1, +1, +3, +5, or +7
Oxygen can be either -2 or +2
Every reactant has to equal zero if there is not a given charge.
Each element can only have certain charges, for example in the previous answer K = +5. Potassium can only be the charge of +1
Chlorine was reduced and oxygen was oxidized in the reaction as shown.
The oxidation number of an atom in a compound is the charge that the atom appears to have as determined by a certain set of rules.
On the left hand side, the oxidation numbers of the elements are;
K = +1
Cl = +3
O = -2
On the right hand side;
K = +1
Cl = -1
O = zero
The element that was oxidized is oxygen. Its oxidation number increased from -2 to zero. The element that was reduced is chlorine. Its oxidation number decreased from +3 to -1.
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