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Solve the right triangle. State the side lengths to the nearest tenth and the angle measures to the nearest degree.

Solve the right triangle State the side lengths to the nearest tenth and the angle measures to the nearest degree class=

Respuesta :

Answer:

Option B

Step-by-step explanation:

The two acute angles of a right triangle are equal.

[tex] \angle \: A + 18 = 180[/tex]

[tex]\angle \: A= 90 - 18 = 72 \degree[/tex]

Recall the mnemonics SOH-CAH-TOA

The tangent ratio is opposite over adjacent.

[tex] \tan(18) = \frac{AC}{21} [/tex]

[tex]AC = 21 \tan(18) [/tex]

[tex]AC = 6.8[/tex]

The sine ratio is opposite over hypotenuse

Using the sine ratio,

[tex] \sin(72) = \frac{21}{AB} [/tex]

[tex]AB = \frac{21}{ \sin(72) } = 22.1[/tex]

Answer:

it 55

Step-by-step explanation: