The system of inequalities y>1/3x+5 and y<1/3x-1 has no solution (parallel lines).
How to draw regions covered by inequalities?
Suppose there is inequality given as: y ≥ f(x)
The region it covers is the region of value pairs (x,y) for which this inequality holds true.
We've to draw the region covered by it.
For a function y = f(x), there is y > f(x) on one side of the graph of the function y = f(x) in XY plane, and on other side there is y < f(x).
The system of inequalities are;
y > 1/3x + 5
The solution of inequality A is the shaded area below the dashed line
y = 1/3x + 5
The slope of line is m = 1/3
Similarly,
y < 1/3x - 1
The solution to inequality B is the shaded area below the dashed line
y = 1/3x - 1
The slope of line is m = 1/3
Thus, The system of inequalities y>1/3x+5 and y<1/3x-1 has no solution (parallel lines).
Learn more about graphing inequalities here:
https://brainly.com/question/19598687
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