The net ionic equation for this reaction is [tex]Fe(s) \ + \ Cu^{2+}(aq) \ \rightarrow \ Fe^{2+}(aq) \ + \ Cu(s)[/tex]. In ionic equations the soluble compounds are written in their dissociated ion forms. The ionic equation can be determined by knowing the general solubility rules. In this problem there are sulfate compounds involved. It is important to know that sulfates are generally soluble except for sulfates of Ba, Pb, Ag, and Sr. Therefore, the ones dealt with in this problem, CuSO4 and FeSO4, are both soluble in water.
Further Explanation:
The complete equation for this reaction is:
[tex]Fe(s) \ + \ CuSO_{4}(aq) \rightarrow \ FeSO_{4}(aq) \ + \ Cu(s)[/tex]
CuSO4 and FeSO4 are soluble in water which will lead to the ionic equation:
[tex]Fe(s) \ + \ Cu^{2+}(aq) \ + \ SO_{4}^ {2-}(aq) \ \rightarrow \ Fe^{2+}(aq) \ + \ SO_{4}^{2-}(aq) \ + \ Cu(s)[/tex]
Since the sulfate ion appears on both sides, it is a spectator ion. Spectator ions are unchanged in the chemical reaction and are removed from the net ionic equation:
[tex]\boxed {Fe(s) \ + \ Cu^{2+}(aq) \ \rightarrow \ Fe^{2+}(aq) \ + \ Cu(s)}[/tex]
Based on the net ionic equation it can be seen that this is a reduction-oxidation reaction. Iron was oxidized and copper was reduced.
Learn More
- Learn more about solubility rules https://brainly.com/question/11617954
- Learn more about redox reactions https://brainly.com/question/2388654
- Learn more about chemical equations https://brainly.com/question/6976143
Keywords: ionic equation, solubility
