Answer:
[tex]x=\frac{-(-2)+-\sqrt{(-2)^{2}-4(3)(0)}}{2(3)}[/tex]
Step-by-step explanation:
* Lets revise the general form of the quadratic equation
- The general form of the quadratic equation is Ax² + Bx + C = 0,
where A , B , C are constant
# A is the coefficient of x²
# B is the coefficient of x
# C is the numerical term
- The quadratic formula is [tex]x=\frac{-B+-\sqrt{B^{2}-4AC }}{2A}[/tex]
* Lets solve the problem
∵ 1 = -2x + 3x² + 1
- Subtract 1 from both side
∴ 0 = -2x + 3x²
- Switch the two sides
∴ -2x + 3x² = 0
- Arrange the equation from the greatest power of x to the smallest
∴ 3x² - 2x = 0
∵ A is the coefficient of x²
∴ A = 3
∵ B is the coefficient of x
∴ B = -2
∵ C is the numerical term
∵ There is no numerical term
∴ C = 0
- Substitute the values of A , B , C in the formula
∴ [tex]x=\frac{-(-2)+-\sqrt{(-2)^{2}-4(3)(0)}}{2(3)}[/tex]
