Answer:
The dimensions of the flower bed before the increase are x ft by (x+11) ft
Step-by-step explanation:
Let
A -----> the area of the flower bed before the increase
B -----> the area of the enlarged flower bed
we know that
[tex]B=A+24[/tex] -----> equation A
we have that
[tex]B=(x^{2} +11x+24)\ ft^{2}[/tex] -----> equation B
substitute equation B in equation A
[tex]x^{2} +11x+24=A+24[/tex]
Solve for A
[tex]A=x^{2} +11x[/tex]
Factor x
[tex]A=x(x+11)\ ft^{2}[/tex] ---> area of the flower bed before the increase
Remember that the area of a rectangle is equal to multiply the length by the width
so
[tex]L=(x+11)\ ft[/tex]
[tex]W=x\ ft[/tex]
therefore
The dimensions of the flower bed before the increase are x ft by (x+11) ft