quincybro0909
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The slope intercept forth of the equation of a line that passes through point (-2, -13) is y = 5x - 3. What is the point slope
form of the equation for this line?

Respuesta :

gmany

Answer:

y + 13 = 5(x + 2)

Step-by-step explanation:

The point-slope form of an equation:

[tex]y-y_1=m(x-x_1)[/tex]

m - slope

The slope-intercept form of an equation of a line:

[tex]y=mx+b[/tex]

m - slope

b - y-intercept

We have the equation of a line:

[tex]y=5x-3[/tex]

therefore the slope m = 5.

Put the value of the slope and the coordinates of the given point (-2, -13) to the equation of a line:

[tex]y-(-13)=5(x-(-2))\\\\y+13=5(x+2)[/tex]

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