A new game is being introduced at the Hard Rock Cafe. A ball is spun around a wheel until it comes to rest in one of many spots. Whatever is listed in that spot will be the player's winnings. If the wheel has 9 spots labeled $1, 18 spots labeled $2, and 1 spots labeled $10, how much should a player expect to win on average? Round to the nearest cent. Your Answer: Question 5 options: Answer

Respuesta :

Answer:

$ 1.96

Step-by-step explanation:

Number of spots with outcome of $1 = 9

Number of spots with outcome of $2 = 18

Number of spots with outcome of $10 = 1

Total number of spots = 28

Probability that ball will land on $1 = [tex]\frac{9}{28}[/tex]

Probability that ball will land on $2 = [tex]\frac{18}{28}[/tex]

Probability that ball will land on $10 = [tex]\frac{1}{28}[/tex]

The amount that player should expect to win on average in equal to expected value of the game. Expected value is calculated as the summation of product of probabilities with their respective outcomes.

i.e. for this case:

Expected Value will be:

[tex](1 \times \frac{9}{28})+(2 \times \frac{18}{28})+(10 \times \frac{1}{28})\\\\ =1.96[/tex]

This means, on average the player should expect to win $ 1.96

Probability is the ratio of the favorable event to the total number of events. The average amount is $1.96.

What is probability?

Probability means possibility. It deals with the occurrence of a random event. The value of probability can only be from 0 to 1. Its basic meaning is something is likely to happen.

A new game is being introduced at the Hard Rock Cafe.

A ball is spun around a wheel until it comes to rest in one of many spots. Whatever is listed in that spot will be the player's winnings.

If the wheel following spots

Number of spots labeled $1 = 9

Number of spots labeled $2 = 18

Number of spots labeled $10 = 1

The total number of spots will be

Total spots = 28

The probability of the ball landing on $1 will be

[tex]\rm P(\$1) = \dfrac{9}{28}[/tex]

The probability of the ball landing on $2 will be

[tex]\rm P(\$2) = \dfrac{18}{28}[/tex]

The probability of the ball landing on $10 will be

[tex]\rm P(\$10) = \dfrac{1}{28}[/tex]

The amount that player should expect to win on average is equal to the expected value of the game will be

[tex]\rm Average\ amount = 1*\dfrac{9}{28} + 2*\dfrac{18}{28} + 10*\dfrac{1}{28}\\\\\\Average \ amount = 1.96[/tex]

More about the probability link is given below.

https://brainly.com/question/795909