Respuesta :
Answer:
(a): The frequency of the waves is f= 0.16 Hz
Explanation:
T/4= 1.5 s
T= 6 sec
f= 1/T
f= 0.16 Hz (a)
(a) The frequency of the waves is ¹/₆ Hz ≈ 0.167 Hz
(b) The speed of the waves is 5¹/₃ m/s ≈ 5.33 m/s
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Further explanation
Let's recall the speed of wave and intensity of wave formula as follows:
[tex]\large {\boxed {v = \lambda f}}[/tex]
f = frequency of wave ( Hz )
v = speed of wave ( m/s )
λ = wavelength ( m )
[tex]\texttt{ }[/tex]
[tex]\large {\boxed {I = 2 \pi^2 A^2 f^2 \rho v}}[/tex]
I = intensity of wave ( W/m² )
A = amplitude of wave ( m )
f = frequeny of wave ( Hz )
ρ = density of medium ( kg/m³ )
v = speed of wave ( m/s )
Let's tackle the problem!
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Given:
time taken = t = 1.50 seconds
distance covered = d = 8.00 m
Asked:
(a) frequency of the waves = ?
(b) speed of the waves = ?
Solution:
Question (a):
[tex]t = \frac{1}{4}T[/tex]
[tex]1.50 = \frac{1}{4}T[/tex]
[tex]T = 4 \times 1.50[/tex]
[tex]T = 6 \texttt{ seconds}[/tex]
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[tex]f = \frac{1}{T}[/tex]
[tex]f = \frac{1}{6} \texttt{ Hz}[/tex]
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Question (b):
[tex]d = \frac{1}{4}\lambda[/tex]
[tex]8.00 = \frac{1}{4}\lambda[/tex]
[tex]\lambda = 8.00 \times 4[/tex]
[tex]\lambda = 32 \texttt{ m}[/tex]
[tex]\texttt{ }[/tex]
[tex]v = \lambda f[/tex]
[tex]v = 32 \times \frac{1}{6}[/tex]
[tex]v = 5\frac{1}{3} \texttt{ m/s}[/tex]
[tex]\texttt{ }[/tex]
Learn more
- Doppler Effect : https://brainly.com/question/3841958
- Example of Doppler Effect : https://brainly.com/question/810552
- Sound Waves Cannot Travel In Space. : https://brainly.com/question/546436
- Frequency of The Beats - Doppler Effect : https://brainly.com/question/12367463
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Answer details
Grade: College
Subject: Physics
Chapter: Sound Waves
