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Mark is flying a kite and realizes that 300 feet of string is out. Mark anchored the kite to the ground. The angle of the string with the ground is 42.5∘. How high is Mark's kite above the ground? Find your answer to the nearest tenth.

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absor201

Answer:

The kite is 202.7 feet above the ground

Step-by-step explanation:

The scenario is depictedd in the picture attached

we have to find the height.

Trigonometric ratios will be used to find the height.

So,

[tex]sin\ (42.5) = \frac{h}{300}\\ 0.6756=\frac{h}{300}\\0.6756*300=h\\202.68 = h[/tex]

The height is 202.68 feet

Rounding off to the nearest tenth

202.7 feet

Therefore, the kite is 202.7 feet above the ground ..

Ver imagen absor201
abiolataiwo2015

Assuming Mark anchored the kite to the ground. How high is Mark's kite above the ground is 202.7 feet.

Height above the ground

Given:

AC=300 feet

CB=42.5°

Hence:

SinC=AB/AC

AB=AC-SinC

300×0.6756

202.67 feet

202.7 feet (Approximately)

Inconclusion assuming Mark anchored the kite to the ground. How high is Mark's kite above the ground is 202.7 feet.

Learn more about Height above the ground here:https://brainly.com/question/27030273

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