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Assume that each tablet's mass was 1,000 mg, and remember that you used 0,200 L of water each time,
Compute the reaction rate to the nearest whole number using the formula below,
mass of tablet/volume of water
Reaction Rate = mas
reaction time
3°C Reaction time = 138.5 sec
Reaction rate = mg/l/sec
24°C Reaction time = 34,2 sec
Reaction rate = mg/L/sec
40°C Reaction time = 26.3 sec
Reaction rate = mg/L/sec
65°C Reaction time = 14.2 sec
Reaction rate = mg/L/sec

Assume that each tablets mass was 1000 mg and remember that you used 0200 L of water each time Compute the reaction rate to the nearest whole number using the f class=

Respuesta :

Answer :

The reaction rate at [tex]3^oC[/tex] is, 36.1 mg/L/sec

The reaction rate at [tex]24^oC[/tex] is, 146.2 mg/L/sec

The reaction rate at [tex]40^oC[/tex] is, 190.1 mg/L/sec

The reaction rate at [tex]65^oC[/tex] is, 352.1 mg/L/sec

Explanation :

Formula used :

[tex]\text{Reaction time}=\frac{(\text{Mass of tablet })/(\text{ volume of water})}{\text{Reaction time}}[/tex]

For [tex]3^oC[/tex] :

[tex]\text{Reaction time}=\frac{(1000mg)/(0.200L)}{138.5sec}=36.1mg/L/sec[/tex]

For [tex]24^oC[/tex] :

[tex]\text{Reaction time}=\frac{(1000mg)/(0.200L)}{34.2sec}=146.2mg/L/sec[/tex]

For [tex]40^oC[/tex] :

[tex]\text{Reaction time}=\frac{(1000mg)/(0.200L)}{26.3sec}=190.1mg/L/sec[/tex]

For [tex]65^oC[/tex] :

[tex]\text{Reaction time}=\frac{(1000mg)/(0.200L)}{14.2sec}=352.1mg/L/sec[/tex]

As we increase the temperature reaction rate is increasing. At [tex]\rm \bold {3^oC}[/tex] the reaction rate is 36.1 mg/L/sec, which increased to 352.1 mg/L/sec at [tex]\rm \bold {65^oC}[/tex].

Reaction Rate:

It means how fast the reactants convert to products in the reaction. It is measured in mg/L/sec.

As given here,

[tex]\texttt{Reaction rate} = \frac{ ( \texttt{Mass of Tablet} )/(\texttt{volume of water} )}{\texttt{Reaction time}}[/tex]

1.Reaction at [tex]\rm \bold {3^oC}[/tex]

[tex]\rm \bold {\texttt{Reaction rate} = \frac{ ( \texttt{1000} )/(\texttt{0.2 L } )}{\texttt{138.5 sec} } = 36.1 mg /L /sec}[/tex]

2. Reaction at [tex]\rm \bold {24^oC}[/tex]

[tex]\rm \bold {\texttt{Reaction rate} = \frac{ ( \texttt{1000} )/(\texttt{0.2 L } )}{\texttt{ 34.2 sec} } = 146.2 mg /L /sec}[/tex]

3. Reaction at [tex]\rm \bold {40^oC}[/tex]

[tex]\rm \bold {\texttt{Reaction rate} = \frac{ ( \texttt{1000} )/(\texttt{0.2 L } )}{\texttt{ 26.3 sec} } = 190.1 mg /L /sec}[/tex]

4.Reaction at [tex]\rm \bold {65^oC}[/tex]

[tex]\rm \bold {\texttt{Reaction rate} = \frac{ ( \texttt{1000} )/(\texttt{0.2 L } )}{\texttt{ 14.2sec} } = 352.1 mg /L /sec}[/tex]

Hence, we can calculate that as we increase the temperature reaction rate is increasing.

To know more about rate of reaction, refer to the link:

https://brainly.com/question/3334857

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