Answer:
y = negative two thirdsx + 6
Step-by-step explanation:
Given points are:
(0,6) and (9,0)
We have to find the slope of the line first
Let
(x_1,y_1) = (0,6)
(x_2, y_2) = (9,0)
[tex]Slope = m = \frac{y_2-y_1}{x_2-x_1}\\ = \frac{0-6}{9-0}\\ =\frac{-6}{9}\\= \frac{-2}{3}[/tex]
The standard from of equation is:
[tex]y=mx+b[/tex]
We have to put the value of m and point in order to find the value of b
[tex]Putting\ (0,6)\ into\ the\ equation\\6 = 0 * \frac{-2}{3} +b\\ 6 = b[/tex]
Putting the value of b and m in standard form
[tex]y = -\frac{2}{3}x+6[/tex]
Therefore, y = negative two thirdsx + 6 is the correct answer ..
Answer:
y = negative two thirdsx + 6
Step-by-step explanation:
