Respuesta :
Answer:
(3x-5)(x+1)
Step-by-step explanation:
For a general polynomial ax^2+bx+c, we need to find two numbers that multiply to ac and add up to b.
In this case, we need to find two numbers that multiply to 3*(-5) = -15 and add up to -2. These are 3,-5. Rewrite the polynomial as:
3x^2+3x-5x-5
And then factor each pair:
3x(x+1)-5(x+1) = (3x-5)(x+1)
Answer:
(x + 1)(3x - 5)
Step-by-step explanation:
Given
3x² - 2x - 5
To factor the quadratic
Consider the factors of the coefficient of the x² term and the constant term which sum to give the coefficient of the x- term
product = 3 × - 5 = - 15 and sum = - 2
The required factors are - 5 and + 3
Use these factors to split the x- term
3x² + 3x - 5x - 5 ( factor the first/second and third/fourth terms )
= 3x(x + 1) - 5(x + 1) ← factor out (x + 1) from each term
= (x + 1)(3x - 5) ← in factored form
