Answer:
18.4 s
Explanation:
The time constant of an RC circuit is given by
[tex]\tau = RC[/tex]
where
R is the resistance
C is the capacitance
For the first circuit we have
[tex]\tau = 4.6 s[/tex]
[tex]R=1.4\cdot 10^4 \Omega[/tex]
So we can find the capacitance
[tex]C=\frac{\tau}{R}=\frac{4.6 s}{1.4\cdot 10^4 \Omega}=3.29\cdot 10^{-4} F[/tex]
Now in the second circuit, the new resistance is
[tex]R=5.6\cdot 10^4 \Omega[/tex]
So the new time constant will be
[tex]\tau = RC=(5.6\cdot 10^4 \Omega )(3.29\cdot 10^{-4} F)=18.4 s[/tex]
The time constant of this electric circuit would be equal to 18.4 seconds.
Given the following data:
Time constant = 4.6 seconds.
Resistance = 1.4 x [tex]10^4[/tex] Ohms.
Mathematically, the time constant of an electric circuit is given by this formula:
[tex]t = RC[/tex]
Where:
Making C the subject of formula, we have:
[tex]C=\frac{t}{R} \\\\C=\frac{4.6}{1.4 \times 10^4} \\\\C=3.29 \times 10^{-4}\;C[/tex]
When R = 5.6 x [tex]10^4[/tex] Ohms, we have:
[tex]t = RC\\\\t= 5.6 \times 10^4 \times 3.29 \times 10^{-4}[/tex]
Time constant, t = 18.4 seconds.
Read more on time constant here: brainly.com/question/4313738
