Answer:
Leg side along the wall = x ft = 8 ft
The other leg side = 7+x ft = 7+8=15 ft
The Hypotenuse =9+x ft = 9+8 = 17 ft
Step-by-step explanation:
In the question, the shape of the pool is right triangle.
Let the leg side along the wall to be the x ft
Let the other leg side to be 7+x ft
Let the longest side/hypotenuse to be x+9 ft
Apply the Pythagorean relationship where the sum of squares of the legs equals the square of the hypotenuse
This means;
[tex]x^2 +(x+7)^2=(x+9)^2\\\\[/tex]
Expand the terms in brackets
[tex]x^2+(x+7)^2=(x+9)^2\\\\\\x^2+x^2+14x+49=x^2+18x+81[/tex]
collect like terms
[tex]x^2+x^2-x^2=18x-14x+81-49\\\\\\x^2=4x+32\\\\\\x^2-4x-32=0[/tex]
solve for x in the quadratic equation by factorization
[tex]x^2-4x-32=0\\\\\\x^2-8x+4x-32=0\\\\\\x(x-8)+4(x-8)=0\\\\\\(x+4)(x-8)=0\\\\\\x+4=0,x=-4\\\\x-8=0,x=8[/tex]
Taking the positive value of x;
x=8ft
Finding the lengths
Leg side along the wall = x ft = 8 ft
The other leg side = 7+x ft = 7+8=15 ft
The Hypotenuse =9+x ft = 9+8 = 17 ft
