A person ingests 0.053 mg of silver ions daily if they drank eight glasses of city water each day.
Further Explanation:
To solve the problem, the following equalities must be used:
0.028 ppm = 0.028 mg/L
1 glass = 8 oz
1 L = 33.8140 oz
The solution to this problem involves two steps:
STEP 1: To get the amount of silver ions in milligrams, first, determine how many liters of water are consumed daily if a person drinks 8 glasses per day. Here, the relationship below are needed:
1 L = 33.8140 oz
1 glass = 8 oz
[tex]volume \ in \ L \ = 8 \ glasses \ (\frac{8 \ oz}{1 \ glass})(\frac{1 \ L}{33.8140 \ oz})[/tex]
Solving the equation gives the volume of city water ingested per day in L:
[tex]\boxed {volume \ in \ L \ = 1.893 \ L}[/tex]
STEP 2: Now that the amount of water is known, calculate the amount of Ag+ present in it using the concentration given. Here, the relationship below is important:
0.028 ppm = 0.028 mg/L
[tex]amount \ of \ Ag^{+} \ = \ 1.893 \ L \ (\frac{0.028 \ mg \ Ag^{+}}{1 \ L})[/tex]
Solving the equation gives the amount of silver ions per eight glasses of water:[tex]amount \ of \ Ag^{+} \ = \ 0.053004 \ mg[/tex]
Since the given 0.028 ppm only has 2 significant figures, the answer must also have 2 significant figures.
Therefore, the final answer is:
[tex]\boxed {amount \ of \ Ag^{+} \ = 0.053 \ mg}[/tex]
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Keywords: parts per million, concentration
