Answer:
final temperature is t = 19.92 °C
Explanation:
from the conservation of energy principle
Heat lost by the steel ball is equal to the heat gained by water and it is given as
[tex]m*c*\delta t = m'c'\delta t'[/tex]
Where
m = mass of steel ball = 31.15 g
c = specific heat of steel = 0.474 J / g -°C
\delta t = change in temperature of steel ball = 103.27°C - t
where , t = final temperature of the system
m' = mass of water = 110.30 g
c ' = specific heat of water = 4.186 J/g-°C
[tex]\delta t'[/tex] = change in temperature of water = t-22.59
after putting all values we get
[tex]m*c*\delta t = m'c'\delta t'[/tex]
31.15*0.474*(103.27°C - t) = 110.30*4.186*(t-22.59)
final temperature is t = 19.92 °C
