Answer:
The magnitude of the velocity of a point P located on its rim after 2 revolutions is V= 0.814 m/s.
The magnitude of the acceleration of a point P located on its rim after 2 revolutions is a= 3.31 m/s².
Explanation:
α= 0.5 rad/s²
r= 0.2 m
ωi= 2 rad/s
θf= 4π rad
a=?
Vt=?
θf=ωi * t + 1/2 * α * t²
clearing t: (time to rotate 2 revolutions)
t= 4.14 s
ωf= ωi + α* t
ωf= 4.07 rad/s
Vt= ωf * r
Vt= 0.814 m/s
ac= ωf² * r
ac= 3.31m/s²
at= α * r
at= 0.1 m/s²
a= √(ac² + at²)
a= 3.31 m/s²
