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In triangle ABC AD/DB = CE/EB. Complete the proof showing the segment DE is parallel to segment AC.


1.

a) (AD/DB) + 1 = (CE/EB) + 1

b) (AD/DB) + DE = (CE/EB) + DE

c) AD * EB = CE * DB


2.

a) Corresponding sides of congruent triangles are congruent.

b) Addition Property of Equality

c) cross multiplication


Edit: Answer is 1.A and 2.B (verified correct) thanks to
https://brainly.com/question/1428177

In triangle ABC ADDB CEEB Complete the proof showing the segment DE is parallel to segment AC1a ADDB 1 CEEB 1 b ADDB DE CEEB DE c AD EB CE DB2a Corresponding si class=

Respuesta :

frika

Answer:

1. [tex]\dfrac{AD}{DB}+1=\dfrac{CE}{EB}+1[/tex]

2. Addition property of equality

Step-by-step explanation:

In triangle ABC,

[tex]\dfrac{AD}{DB}=\dfrac{CE}{EB}.[/tex]

The addition property of equality states that if the same amount is added to both sides of an equation, then the equality is still true.

Use addition property of equality, add 1 to both sides of previouse equality:

[tex]\dfrac{AD}{DB}=\dfrac{CE}{EB}\\ \\\dfrac{AD}{DB}+1=\dfrac{CE}{EB}+1\\ \\\dfrac{AD+DB}{DB}=\dfrac{CE+EB}{EB}[/tex]

85498

Answer:

(AD/DB) +1 = (CE/EB) +1 -----> Addition Property of Equality

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