Answer:
The answer in the procedure
Step-by-step explanation:
step 1
Find the length sides of the triangle
Given the coordinates
A(a1,a2), B(b1,b2) and C(c1,c2)
we know that
the formula to calculate the distance between two points is equal to
[tex]d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}[/tex]
so
Calculate
dAB,dBC and dAC
substitute in the formula
[tex]dAB=\sqrt{(b2-a2)^{2}+(b1-a1)^{2}}[/tex]
[tex]dBC=\sqrt{(c2-b2)^{2}+(c1-c1)^{2}}[/tex]
[tex]dAC=\sqrt{(c2-a2)^{2}+(c1-a1)^{2}}[/tex]
step 2
Apply Pythagoras theorem
[tex]c^{2}=a^{2}+b^{2}[/tex]
where
c is the greater side
a and b are the other two sides
substitute the distances in the equation
If the equation is true
therefore
Its a right triangle
