Answer:
[tex]\frac{3}{4}[/tex]
Step-by-step explanation:
This is a question from conditional probability.
We are given:
[tex]P(A \cap B) = \frac{3}{10}[/tex]
[tex]P(B)=\frac{2}{5}[/tex]
And, we need to find P(A | B)
According to the formula of conditional probability:
[tex]P(A|B)=\frac{P(A \cap B)}{P(B)}[/tex]
Using the values, we get:
[tex]P(A|B)=\frac{\frac{3}{10} }{\frac{2}{5} }\\\\P(A|B)=\frac{3}{4}[/tex]
Thus, the probability of occurrence of event A given that event B has already occurred is [tex]\frac{3}{4}[/tex]
