Answer:1547.9 miles per hour
Step-by-step explanation:
Let the two trains leave in x direction and y direction
Velocity of train in x direction be v
therefore velocity of train in Y direction is v+29
because one train is 29 miles per hour slower than other.
Distance travel by train in x direction is(x) v(2)
Distance travel by train in y direction is(y) 2(v+29)
distance between them after 2 hours is 4420 miles
Now using pythagoras theorem
[tex]x^2+y^2=\left ( 4420\right )^2[/tex]
[tex]\left ( 2v\right )^2+\left ( 2\left ( v+29\right )\right )^2=\left ( 4420\right )[/tex]
on solving
[tex]2v^2+58v-4881699=0[/tex]
v=[tex]\frac{-58\pm \sqrt{\left ( 58 \right )^2+4\cdot 2\cdot4881699}}{2\cdot 2}[/tex]
v=1547.889 miles per hour
