maaxanaya
contestada

A farmer is tracking the amount of corn his land is yielding each year. He finds that the function f(x) = −x2 + 20x + 50 models the crops in pounds per acre over x years. Find and interpret the average rate of change from year 1 to year 10. The crop yield increased by 9 pounds per acre from year 1 to year 10. The crop yield decreased by 0.09 pounds per acre from year 1 to year 10. The crop yield decreased by 11 pounds per acre from year 1 to year 10. The crop yield increased by 99 pounds per acre from year 1 to year 10.

Respuesta :

kudzordzifrancis

Answer:

The crop yield decreased by 0.09 pounds per acre from year 1 to year 10

Step-by-step explanation:

The function that models the crops in pounds per acre over x years is

[tex]f(x)=-x^2+20x+50[/tex]

In year 1, the crop yield is [tex]f(1)=-(1)^2+20(1)+50=69[/tex]

In year 10, the crop yield is [tex]f(10)=-(10)^2+20(10)+50=150[/tex]

The average rate of change from year 1 to year 10 is given by:

[tex]\frac{f(10)-f(1)}{10-1}[/tex]

We substitute the values to get:

[tex]\frac{150-69}{10-1}[/tex]

[tex]=\frac{81}{9}=9[/tex]

Since the average rate of change is positive, the crop yield decreased by 0.09 pounds per acre from year 1 to year 10.

qwerty1128

Answer: The crop yield increased by 9 pounds per acre from year 1 to year 10.

Step-by-step explanation:

To solve this we are using the average rate of change formula: Av=\frac{f(x_2)-f(x_1)}{x_2-x_1}, where:

x_2 is the second point in the function

x_1 is the first point in the function

f(x_2) is the function evaluated at the second point

f(x_1) is the function evaluated at the first point

We know that the first point is 1 year and the second point is 10 years, so x_1=1 and x_2=10. Replacing values:

Av=\frac{-(10)^2+20(10)+50-[-(1)^2+20(1)+50]}{10-1}

Av=\frac{-100+200+50-[-1+20+50]}{9}

Av=\frac{150-[69]}{9}

Av=\frac{150-69}{9}

Av=\frac{81}{9}

Av=9

Since f(x) represents the number of pounds per acre and x the number of years, we can conclude that the crop yield increased by 9 pounds per acre from year 1 to year 10.

Otras preguntas