Answer:
3.33 meters per second
Step-by-step explanation:
you must find the total time that Mr. B spent to complete the swim and bike.
Information:
0h 25' 10'' ---------> Swim
1h 30' 50'' ---------> Bike
[tex]hours = 0 + 1 = 1\\minutes = 25+30 = 55\\seconds = 10+50=60\\[/tex]
he spent 1h 55' 60'', this is 1h 56'.
now you must substract this time from the record time to find the time alloted to run:
first you convert both times into minutes:
[tex]record \ time = 2(60) + 46 = 166 \ minutes \ \ \ \ multiply \ hours \ by \ 60 \ minutes\\time\ swim \ and \ bike = 1(60) + 56 = 116 \ minutes\\[/tex]
now substracting:
[tex]time \ to \ run \ = record \ time \ - \ time \ swim \ and \ bike\\time \ to \ run \ = 166 - 116 = 50 \ minutes[/tex]
so he must travel 10 km in 50 minutes, that is:
speed = distance/time
[tex]speed = \frac{10}{50} \frac{km}{min}[/tex]
1 km is equal to 1000 meters and 1 minute is equal to 60 seconds.
[tex]speed = \frac{(10)}{(50)}\frac{(1000) meters}{(60) sec}\\\\speed = \frac{(10000)}{(3000)}\frac{meters}{sec} \ \ \ \ \ \ \ \ \ multiply \\\\speed = 3.33 \ meters/sec[/tex]
so Mr.B's speed must be 3.33 meters/sec
