Respuesta :

wegnerkolmp2741o

Answer:

(3g+4) (2g^2-5)

Step-by-step explanation:

6g^3 + 8g^2 - 15g - 20

Lets factor by grouping

Taking a 2 g^2 out of the first two terms and -5 out of the last two terms

2g^2 (3g+4) -5(3g+4)

Factoring out (3g+4)

(3g+4) (2g^2-5)

absor201

Answer:

The factors are (3g+4)(2g^2-5)....

Step-by-step explanation:

The expression is:

6g^3 + 8g^2 - 15g - 20

Make a group of the first two terms and last two terms:

(6g^3 + 8g^2) - (15g + 20)

Now factor out the common from each group:

2g^2(3g+4)-5(3g+4)

(3g+4)(2g^2-5)

Therefore the factors are (3g+4)(2g^2-5)....

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