Answer:
The ratio acid to water in the mixture is 2:3
Explanation:
Let the volume of 20% acid solution used to make the mixture = x units
So, the volume of 50% acid solution used to make the mixture = 2x units
Total volume of the mixture = x + 2x = 3x units
For 20% acid solution:
C₁ = 20% , V₁ = x
For 50% acid solution :
C₂ = 50% , V₂ = 2x
For the resultant solution of sulfuric acid:
C₃ = ? , V₃ = 3x
Using
C₁V₁ + C₂V₂ = C₃V₃
20×x + 50×2x = C₃×3x
So,
20 + 50×2 = C₃×3
Solving
120 = C₃×3
C₃ = 40 %
Thus, for the resultant mixture,
Acid percentage = 40%
Water percentage = (100 - 40)% = 60%
Ratio acid to water in the mixture = 40:60 = 2:3
