Respuesta :
Answer:
750 mm
Explanation:
Given:
d = 1.8 mm
R = 4.8 m
m = 5
y = 1
Using the equation
y = (mLR)/d ,
where,
m gives a distance 'y' to that particular slit image.
R = distance from the double slits to the screen
d = double slit separation distance.
L = wavelength of the light.
substituting the values in the given equation
we get
L = [tex]\frac{1\times 1.8\times 10^{-3}}{5\times 4.8}[/tex]
or
L = 750 mm
Answer:
The wavelength of the monochromatic light is [tex]7.5\times10^{-7}\ m[/tex]
Explanation:
Given that,
Distance between the slits d = 1.8 mm
Distance of fringe from the slits D =4.8 m
Number of fringe m =1
Distance between the fringes = 1 cm
We need to calculate the wavelength of monochromatic light
Using formula of young's double slits
[tex]\lambda=\dfrac{Yd}{mD}[/tex]
Where, d = Distance between the slits
D = Distance of fringe from the slits
m = Number of fringe
y = Distance between the fringes
Put the value in to the formula
[tex]\lambda=\dfrac{1\times10^{-2}\times1.8\times10^{-3}}{5\times4.8}[/tex]
[tex]\lambda =7.5\times10^{-7}\ m[/tex]
Hence, The wavelength of the monochromatic light is [tex]7.5\times10^{-7}\ m[/tex]
