A flagpole 94.9 ft tall is on the top of a building. From a point on level​ ground, the angle of elevation of the top of the flagpole is 35.3degrees​, while the angle of elevation of the bottom of the flagpole is 26.2degrees. Find the height of the building.

Respuesta :

Answer:

214 ft

Step-by-step explanation:

Height of building = 94.9 ft

The angle of elevation of the top of the flagpole = θ₁ = 35.3°

The angle of elevation of the bottom of the flagpole = θ₂ = 26.2°

Let,

Height of building = x

Distance from observation point to base of building = y

[tex]tan 26.2 =\frac{x}{y}\\\Rightarrow y=\frac{x}{tan26.2}[/tex]

[tex]tan 35.3 =\frac{94.9+x}{y}\\\Rightarrow tan 35.3 =\frac{94.9+x}{\frac{x}{tan26.2}}\\\Rightarrow \frac{x}{tan26.2}tan35.3=94.9+x\\\Rightarrow \frac{tan35.3}{tan26.2}x-x=94.9\\\Rightarrow x=\frac{94.9}{\frac{tan35.3}{tan26.2}-1}\\\Rightarrow x=214.84/ ft[/tex]

I have used the exact values from the calculator.

∴ Height of the building is 214.84 ft

Ver imagen shirleywashington

Answer:

The height of the building is 214.84 ft.

Step-by-step explanation:

Given information:

The height of the flagpole = 94.9 ft.

The angle of elevation of top = θ[tex]_1[/tex] = [tex]35.3^o[/tex]

The angle of elevation of bottom = θ[tex]_2=26.2^o[/tex]

If the height of building is [tex]x[/tex]

Then,

[tex]tan 26.2=x/y\\y=x/(tan26.2)\\[/tex]

And:

[tex]tan 35.3=(94.9+x)/y\\[/tex]

[tex]94.9+x=y \times tan35.3[/tex]

On putting the value in above equation:

[tex]x=\frac{94.9}{\frac{tan35.3}{tan26.2}-1 }[/tex]

solving the above equation:

[tex]x=214.84 ft.[/tex]

Hence, the height of the building is 214.84 ft.

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