Assume that the heights of men are normally distributed. A random sample of 16 men have a mean height of 67.5 inches and a standard deviation of 3.2 inches. Construct a 99% confidence interval for the population standard deviation, σ. (2.2, 5.4) (2.2, 6.0) (1.2, 3.2) (2.2, 5.8)

Respuesta :

Answer: (2.2, 5.8)

Step-by-step explanation:

The confidence interval for standard deviation is given by :-

[tex]\left ( \sqrt{\dfrac{(n-1)s^2}{\chi^2_{(n-1),\alpha/2}}} , \sqrt{\dfrac{(n-1)s^2}{\chi^2_{(n-1),1-\alpha/2}}}\right )[/tex]

Given :  Sample size : 16

Mean height : [tex]\mu=67.5[/tex] inches

Standard deviation : [tex]s=3.2[/tex] inches

Significance level : [tex]1-0.99=0.01[/tex]

Using Chi-square distribution table ,

[tex]\chi^2_{(15,0.005)}=32.80[/tex]

[tex]\chi^2_{(15,0.995)}=4.60[/tex]

Then , the 99% confidence interval for the population standard deviation is given by :-

[tex]\left ( \sqrt{\dfrac{(15)(3.2)^2}{32.80}} , \sqrt{\dfrac{(15)(3.2)^2}{4.6}}\right )\\\\=\left ( 2.1640071232,5.77852094812\right )\approx\left ( 2.2,5.8 \right )[/tex]