A rigid tank is divided into two equal volumes. One side contains 2 kmol of nitrogen N2 at 500 kPa while the other side contains 8 kmol of CO2 at 200 kPa. The two sides are now connected and the gases are mixed and forming a homogeneous mixture at 250 kPa. Find the partial pressure of the CO2 in the final mixture.

Respuesta :

Answer:

The partial pressure of the [tex]CO_2[/tex] in the final mixture is 200 kPa.

Explanation:

Pressure of nitrogen gas when the two tanks are disconnected = 500 kPa

Pressure of the carbon-dioxide gas when the two tanks are disconnected = 200 kPa

Moles of nitrogen gas =[tex]n_1= 2 kmol[/tex]

Moles of carbon dioxide gas =[tex]n_2=8 kmol[/tex]

After connecting both the tanks:

The total pressure of the both gasses in the tank = p = 250 kPa

According to Dalton' law of partial pressure:

Total pressure is equal to sum of partial pressures of all the gases

Partial pressure of nitrogen =[tex]p_{N_2}^o[/tex]

Partial pressure of carbon dioxide=[tex]p_{CO_2}^o[/tex]

[tex]p_{N_2}^o=p\times \frac{n_1}{n_1+n_2}[/tex]

[tex]p_{N_2}^o=250 kPa\times \frac{0.2}{0.2+0.8}=50 kPa[/tex]

[tex]p_{CO_2}^o=p\times \frac{n_2}{n_1+n_2}[/tex]

[tex]p_{CO_2}^o=250 kPa\times \frac{0.8}{0.2+0.8}=200 kPa[/tex]

The partial pressure of the [tex]CO_2[/tex] in the final mixture is 200 kPa.